0=2n^2-17n+16

Solution for 0=2n^2-17n+16 equation:

0=2n^2-17n+16

We move all terms to the left:

0-(2n^2-17n+16)=0

We add all the numbers together, and all the variables

-(2n^2-17n+16)=0

We get rid of parentheses

-2n^2+17n-16=0

a = -2; b = 17; c = -16;
Δ = b2-4ac
Δ = 172-4·(-2)·(-16)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{161}}{2*-2}=\frac{-17-\sqrt{161}}{-4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{161}}{2*-2}=\frac{-17+\sqrt{161}}{-4}
$